課程影片與練習

課程簡介
第1週:網路架構與七層參考模式簡介
第2週:IEEE 802.3 乙太網路 (Ethernet)
第3週:IEEE 802.11 無線區域網路 (Wireless LAN)
第4週:IEEE 802.1D 交換機的擴張樹演算法 (Spanning Tree Algorithm)
第5週:IEEE 802.1Q 虛擬區域網路 (Virtual LAN)
第7週:路由器運作原理以及網路互連技術
第8週:TCP 與網路阻塞偵測與控制技術

6.14. In the sliding window protocol, the receiver maintains three variables: Receiving Window Size (RWS): Upper bound on the number of out-of-order frames that the receiver is willing to accept; Largest Acceptable Frame (LAF): Sequence number of the largest acceptable frame, and Last Frame Received (LFR): Sequence number of the last frame received.
在滑動視窗協議裡,接收端會維護三個變數: Receiving Window Size (RWS): 接收端同時可接收未按照序號到達的訊框數量上限; Largest Acceptable Frame (LAF): 最大可以接收的訊框序號,以及 Last Frame Received (LFR): 最後收到的訊框序號.

Which of the following relationship is correct for these three variables ? 下列對於這三個變數的關係哪些是正確的 ?

(a) LAF –LFR > RWS
(b) LAF – LFR ≤ RWS
(c) LAF – RWS ≤ LFR
(d) LFR + RWS ≤ LAF
(e) LAF – RWS > LFR

6.15 Consider the three variables defined in question 6.14. Which of the following conditions are right timing for the receiver to slide its window ? 考慮在練習提 6.14 定義的三個變數. 下列哪個是接收端滑動視窗的正確時機 ?

(a) When a frame with sequence number within the sliding window is received 當收到一個訊框而其序號在滑動視窗內
(b) When a frame with sequence number of LFR+1 is received 當收到序號為 LFR+1 的訊框
(c) When a frame with sequence number of LFR +RWS - 1 is received 當接收到序號為 LFR +RWS – 1 的訊框
(d) When a frame with sequence number of LFR +RWS is received 當接收到序號為 LFR +RWS 的訊框
(e) When a frame with sequence number LFR +RWS +1 is received 當接收到序號為 LFR +RWS +1 的訊框

6.16 Consider the three variables defined in question 6.14. When the receiver sliding its window, at most how many sequence numbers can be shifted by the window ? 考慮在練習提 6.14 定義的三個變數. 當接收端滑動其視窗時,最多可以移動多少個序號 ?

(a) 1
(b) 2
(c) RWS-1
(d) RWS
(e) RWS+1

6.17 Consider the three variables defined in question 6.14. Which of the following statements are correct when the receiver receives a frame with sequence number N ?
考慮在練習題 6.14 定義的三個變數. 當接收端接收到一個序號為N的訊框時, 下列哪些敘述是正確的 ?

(a) The receiver will discard the frame if N ≤ LFR. 若 N ≤ LFR,接收端會丟棄此訊框.
(b) The receiver will discard the frame if or N > LAF. 若 N > LAF,接收端會丟棄此訊框.
(c) The receiver will accept the frame if N = LAF + 1 若 N = LAF + 1,接收端會接收此訊框.
(d) The receiver will accept the frame if N = LFR 若 N = LFR,接收端會接受此訊框.
(e) The receiver will accept the frame if LFR < N ≤ LAF 若 LFR < N ≤ LAF,接收端會接受此訊框

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